A sphere is rotating between two rough inclined walls as shown in figure
A
. Coefficient of friction between each wall and the sphere is 1/3. If f 1 and f 2 be the friction forces at P and Q. Then 
is – 
+ 1
is – + 1
B
+ 2
C
+ 
D
1 + 2 
Text Solution
Verified by ExpertsThe correct answer is:
A
Let µ be the friction coefficient between sphere and each wall. Free body diagram of sphere is
Fig.
Net force on the sphere in horizontal direction is zero.
N 1 cos 60 0 + µ N 2 cos 60 0 = N 2 cos 30º + µ N 1 cos 30 0
or N 1 + µN 2 = 
(N 2 + µN 1 )
or N 1 (1 – 
µ) = N 2 ( 
– µ)
= 
Substituting µ = 
we get,
= 
= 
= 1 + 
Now 
= 
= 1 + 
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